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Differential Equations: Second Order Homogeneous Equations

Given a series RLC circuit with the equation Ld2idt2+Rdidt+1Ci=0 L \frac{d^2 i}{dt^2} + R \frac{di}{dt} + \frac{1}{C} i = 0 , where the inductance L=0.2L = 0.2 Henrys, resistance R=330R = 330 Ohms, and capacitance C=20C = 20 microfarads, and initial conditions i(0)=0i(0) = 0 and didt(0)=30 \frac{di}{dt}(0) = 30 , solve the second-order differential equation for the current ii as a function of time tt

What if the characteristic equation does not have real roots, what if they are complex?

Solve a constant coefficient homogeneous linear 2nd order differential equation with complex roots of the form r=1±ir = -1 \pm i. Derive the general solution form.

Find the particular solution for the differential equation y+4y+5y=0y'' + 4y' + 5y = 0 with the initial conditions y(0)=1y(0) = 1 and y(0)=0y'(0) = 0.

What happens when you have two complex roots? Or essentially, when you're trying to solve the characteristic equation, when you're trying to solve that quadratic? The B24ACB^2 - 4AC is negative, so you get the two roots end up being complex conjugates.

Let's say I had the differential equation y+y+y=0y'' + y' + y = 0. What are the roots of the characteristic equation r2+r+1=0r^2 + r + 1 = 0 using the quadratic formula?

Given the second order differential equation yy=6(y)2y y' = 6 (y')^2, solve by making the substitution y=dpdxy' = \frac{dp}{dx} and finding the general solution.

Find the general solution and a second solution of the differential equation x2y+5xy5y=0x^2 y'' + 5x y' - 5y = 0 given that y1=xy_1 = x is a known solution.

Find the general solution to the differential equation: d2ydx2+4dydx+4y=0\frac{d^2y}{dx^2} + 4 \frac{dy}{dx} + 4y = 0.

Derive the general form solution for a second-order constant coefficient linear homogeneous differential equation with repeated roots.

Solve the second-order linear constant coefficient homogeneous equation y2y+y=0y'' - 2y' + y = 0 using the reduction of order method to find a second independent solution.

Find the general solution to the second order linear homogeneous differential equation y+2y+y=0y'' + 2y' + y = 0.

Given a second order linear homogeneous differential equation with a repeated root, find the general solution.

Solve the second order homogeneous linear differential equation 4y5y6y=04y'' - 5y' - 6y = 0 using the method of characteristic equations.

Solve the second order constant coefficient differential equation yy6y=0y'' - y' - 6y = 0 with initial conditions y(0)=1y(0) = 1 and y(0)=2y'(0) = 2.

Solve the differential equation y4y+4y=0y'' - 4y' + 4y = 0.

Solve the differential equation 3y+2y+y=03y'' + 2y' + y = 0.

Solve the initial value problem yy12y=0y'' - y' - 12y = 0 with the initial conditions y(0)=0y(0) = 0 and y(0)=14y'(0) = 14.

Solve the second order linear homogeneous differential equation: y+2y+8y=0y'' + 2y' + 8y = 0 using the quadratic formula to find the characteristic equation roots.