Abstract Algebra: Groups and Subgroups
Collapse
All Abstract AlgebraIntegers and Modular ArithmeticFunctions and MappingsGroups and SubgroupsCyclic and Abelian GroupsHomomorphisms and IsomorphismsCosets Lagranges Theorem and Normal SubgroupsQuotient Groups and the Fundamental TheoremPermutation Groups and Cayleys TheoremClassification of Abelian GroupsRings and SubringsIntegral Domains and FieldsPolynomial Rings
AllMediumEasyHardNeeds AttentionVideo
Suppose we have a set of 2 by 2 matrices whose determinants are non-zero. Consider the subset of these matrices whose determinant is 1. Using the two-step subgroup test, verify if this subset is closed under multiplication and if an element belongs to this subset, confirm that its inverse also belongs to this subset.
Given a finite subset of a group, verify if the subset is closed under the group operation to determine if it is a subgroup.
Suppose we have a non-empty subset of a group . Prove that this subset is a subgroup if and only if for all , .
Show that the centralizer of , defined as , is a subgroup of .
Show that the conjugate subgroup , defined as consisting of elements of the form for , is a subgroup.