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Divergence of Alternating Sign Sequence

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Prove that the sequence an=(1)na_n = (-1)^n diverges.

In this problem, we explore the convergence properties of sequences, specifically focusing on the sequence defined by an=(1)na_n = (-1)^n. This sequence alternates between 1 and -1 for consecutive terms. From a real analysis perspective, the key to understanding this problem lies in the definition of a convergent sequence. A sequence is said to converge to a limit L if, for any given small positive number (epsilon), there exists a point in the sequence beyond which all terms are within epsilon of L. Essentially, the terms of the sequence become arbitrarily close to L as the sequence progresses.

For the sequence an=(1)na_n = (-1)^n, observe that no matter how far you go along the sequence, the terms continue to oscillate between 1 and -1. This behavior indicates that the terms do not settle down to a single value or come arbitrarily close to any single number, a necessary condition for convergence. Thus, we conclude that the sequence diverges. By examining sequences like an=(1)na_n = (-1)^n, students can gain a deeper understanding of the concept of divergence and how it contrasts with convergence. This problem serves as a foundation for understanding the nature of oscillating sequences and their behaviors in the context of real analysis.

Posted by Gregory 4 hours ago

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