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Prove Continuity of Absolute Value Function

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Prove that the function f(x)=xf(x) = |x| is continuous on the real numbers using the epsilon-delta definition.

The challenge presented in this problem is to demonstrate the continuity of the absolute value function using the epsilon-delta definition of continuity. This task requires more than just knowing the abstract definition; it also requires the ability to apply this definition in a concrete, rigorous manner. The function f(x)=xf(x) = |x| is defined for all real numbers and is a piecewise function, which introduces unique considerations when proving continuity using epsilon-delta techniques. Specifically, you need to show that for every positive epsilon, there exists a positive delta such that if the difference between x and a point c is less than delta, then the difference between f(x)f(x) and f(c)f(c) is less than epsilon. This requires analyzing the behavior of the function at x=0x = 0, where the piecewise definition of absolute value changes, and ensuring continuity at that critical point as well as for all other real numbers.

Understanding continuity through the epsilon-delta definition is fundamental in real analysis as it forms the basis for more advanced concepts such as uniform continuity and differentiability. Mastering this type of problem builds a deeper understanding of the nature of continuous functions and prepares you for exploring more complex functions and theorems in the future. By being proficient with making epsilon-delta arguments, students gain insight into the meticulous nature of mathematical proofs and develop skills that are critical for success in higher-level mathematics.

Posted by Gregory 4 hours ago

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