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Sum of First n Natural Numbers Using Induction

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Prove that 1+2+3++n=n(n+1)21 + 2 + 3 + \ldots + n = \frac{n(n+1)}{2} using mathematical induction.

In this problem, we explore a classic result in mathematics: the formula for the sum of the first n natural numbers. The formula states that the sum of numbers from 1 to n is equal to n times (n plus 1) divided by 2. This is often one of the first arithmetic series sums that students encounter and is fundamental in understanding arithmetic progressions more generally.

The problem requires the use of mathematical induction, a powerful proof technique that is particularly suited for propositions that can be framed sequentially. Mathematical induction involves two key steps: the base case and the inductive step. The base case verifies that the property holds for an initial value, typically n equals 1. The inductive step shows that if the property holds for some arbitrary number k, it then holds for k plus 1 as well. Through these steps, you effectively prove that the property holds for all natural numbers.

Understanding this problem will deepen your grasp of how induction works and illustrates its utility in proving statements about natural numbers and sequences. Induction is not only a foundational technique in discrete mathematics but also appears frequently in algorithms and recursive definitions, which makes it a critical tool for computer scientists and mathematicians alike.

Posted by Gregory 8 hours ago

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