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Probability of Drawing Aces and Jacks from a Deck

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Given a deck of 52 cards, what is the probability of drawing three Aces and two Jacks?

This problem presents an interesting application of discrete probability in which the goal is to determine the likelihood of a specific event occurring—drawing three Aces and two Jacks from a deck of 52 cards. The problem requires a strong understanding of combinatorial methods to calculate the number of favorable outcomes and the total possible outcomes.

Students should first consider how to count the number of ways to select three Aces from the four available in the deck. This can be done using combinations, a common tool in discrete mathematics, since the order in which we select the Aces does not matter. Similarly, they should compute the number of ways to select two Jacks from the available four. The product of these two combinations will give the number of favorable ways to draw exactly three Aces and two Jacks.

Another important aspect of solving this problem involves understanding the fundamental principle of counting, specifically the multiplication rule, which applies since selecting Aces and Jacks are independent events. The denominator of the probability will be the number of ways to choose any five cards out of 52, which is another combinatorial calculation. Once both the numerator and the denominator are determined, constructing the probability requires dividing the number of favorable outcomes by the number of total outcomes. This exercise highlights the importance of combinatorial thinking in solving discrete probability problems.

Posted by Gregory 13 hours ago

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