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Converting Differential Equation to Standard Form

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Convert xy+3y=xxy' + 3y = x to y+3xy=1y' + \frac{3}{x}y = 1

In the realm of differential equations, particularly first-order linear differential equations, converting a given equation into a standard form is a critical skill. This involves rearranging terms such that the derivative of the function is isolated on one side. By converting an equation into this standard form, it becomes easier to identify the integrating factor, a common technique for finding solutions. In our problem, transforming the given equation involves algebraic manipulation to isolate the derivative term, making subsequent steps more straightforward. The standard form helps to align with techniques like using an integrating factor, which simplifies the solving process.

Recognizing such equations and applying this conversion is crucial as it sets up for solving through integration methods. Seeing these kinds of transformations will aid in understanding not just how to solve equations but why these manipulations make complex expressions more manageable. Such practices in problem-solving reveal underlying patterns and regularities that not only apply to differential equations but also to broader mathematical contexts.

Posted by Gregory 21 days ago

Related Problems

Solve the differential equation sin(x)dydx+3ycos(x)=csc(x)\sin(x) \frac{dy}{dx} + 3y \cos(x) = \csc(x) using the integrating factor method.

Solve the first-order linear ordinary differential equation: 2xy3y=9x32x \, \cdot \, y' - 3y = 9x^3 using the integrating factor method.

Solve the differential equation y+y=exy' + y = e^x using the integrating factor e1dxe^{\, \int 1 \, dx}.

Solve for y in: x2y+5xy=xx^2 y' + 5xy = x, converting to y+5xy=1xy' + \frac{5}{x}y = \frac{1}{x}