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Equilibrium Solutions of Autonomous Differential Equation

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Given an autonomous differential equation dydt=f(y)\frac{dy}{dt} = f(y) where f(y)=1+y(1y)f(y) = 1 + y (1 - y), identify the equilibrium solutions and determine their stability.

Autonomous differential equations are an important category of ordinary differential equations where the rate of change of the variable is dependent solely on its current state, not explicitly on the independent variable. In this problem, we are tasked with solving the autonomous differential equation dydt=f(y)\frac{dy}{dt} = f(y) where f(y)=1+y(1y)f(y) = 1 + y (1-y). The key focus here is on finding equilibrium solutions which are the values of y for which dydt=0\frac{dy}{dt} = 0. These equilibrium solutions represent the states where the system is in balance and, therefore, experiences no change over time.

Once the equilibrium solutions are identified, the next step involves analyzing the stability of these solutions. Stability analysis is crucial because it allows us to determine the behavior of trajectories near these equilibrium points. If nearby trajectories tend to move towards an equilibrium, it is considered stable; if they move away, it is unstable. This involves calculating the derivative of f(y)f(y) with respect to yy and evaluating it at the equilibrium points, often called the linearization process. If the derivative is negative, the equilibrium is stable, whereas if it is positive, it is unstable.

This problem illustrates the broader mathematical methods used in the study of dynamical systems, especially in fields like biology, economics, and physics, where understanding the stability of systems is crucial for predicting long-term behavior.

Posted by Gregory 21 hours ago

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