# Jump Game

You are given an integer array nums. You are initially positioned at the array's **first index**, and each element in the array represents your maximum jump length at that position.

Return true* if you can reach the last index, or *false* otherwise*.

```
public boolean canJump(int[] nums) {
int reachable = 0;
for (int i=0; i<nums.length; ++i) {
if (i > reachable) return false;
reachable = Math.max(reachable, i + nums[i]);
}
return true;
}
```

## Related Problems

Given an array of intervals where intervals[i] = [starti, endi], merge all overlapping intervals, and return *an array of the non-overlapping intervals that cover all the intervals in the input*.

You are given an array of CPU tasks, each represented by letters A to Z, and a cooling time, n. Each cycle or interval allows the completion of one task. Tasks can be completed in any order, but there's a constraint: **identical** tasks must be separated by at least n intervals due to cooling time.

Return the *minimum number of intervals* required to complete all tasks.

Given an array nums with n integers, your task is to check if it could become non-decreasing by modifying **at most one element**.

We define an array is non-decreasing if nums[i] <= nums[i + 1] holds for every i (**0-based**) such that (0 <= i <= n - 2).

You are given a **0-indexed** array of integers nums of length n. You are initially positioned at nums[0].

Each element nums[i] represents the maximum length of a forward jump from index i. In other words, if you are at nums[i], you can jump to any nums[i + j] where:

0 <= j <= nums[i] and

i + j < n

Return *the minimum number of jumps to reach *nums[n - 1]. The test cases are generated such that you can reach nums[n - 1].