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Regular Expression Matching

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Given an input string s and a pattern p, implement regular expression matching with support for '.' and '*' where:

'.' Matches any single character.

'*' Matches zero or more of the preceding element.

The matching should cover the entire input string (not partial).

class Solution:
    def isMatch(self, s: str, p: str) -> bool:
        m, n = len(s), len(p)
        dp = [[False] * (n+1) for _ in range(m+1)]
        dp[0][0] = True
        for j in range(1, n+1):
            if p[j-1] == '*':
                dp[0][j] = dp[0][j-2]
                dp[0][j] = j > 1 and p[j-2] == '*' and dp[0][j-2]
        for i in range(1, m+1):
            for j in range(1, n+1):
                if p[j-1] == s[i-1] or p[j-1] == '.':
                    dp[i][j] = dp[i-1][j-1]
                elif p[j-1] == '*':
                    dp[i][j] = dp[i][j-2] or (p[j-2] == s[i-1] or p[j-2] == '.') and dp[i-1][j]
                    dp[i][j] = False
        return dp[m][n]

Posted by Jamie Meyer 3 months ago

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