# Longest Palindromic Substring

Given a string s, return *the longest* *palindromicsubstring*in s.

```
public String longestPalindrome(String s) {
int n = s.length();
String res = null;
boolean[][] dp = new boolean[n][n];
for (int i = n - 1; i >= 0; i--) {
for (int j = i; j < n; j++) {
dp[i][j] = s.charAt(i) == s.charAt(j) && (j - i < 3 || dp[i + 1][j - 1]);
if (dp[i][j] && (res == null || j - i + 1 > res.length())) {
res = s.substring(i, j + 1);
}
}
}
return res;
}
```

## Related Problems

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it can trap after raining.

You are given n balloons, indexed from 0 to n - 1. Each balloon is painted with a number on it represented by an array nums. You are asked to burst all the balloons.

If you burst the ith balloon, you will get nums[i - 1] * nums[i] * nums[i + 1] coins. If i - 1 or i + 1 goes out of bounds of the array, then treat it as if there is a balloon with a 1 painted on it.

Return *the maximum coins you can collect by bursting the balloons wisely*.

Given an input string (s) and a pattern (p), implement wildcard pattern matching with support for '?' and '*' where:

'?' Matches any single character.

'*' Matches any sequence of characters (including the empty sequence).

The matching should cover the **entire** input string (not partial).

Given an integer n, return *the number of structurally unique ***BST'***s (binary search trees) which has exactly *n* nodes of unique values from* 1 *to* n.