Skip to Content

Finding Relative Extrema

Home | Calculus 1 | Graphing and Critical Points | Finding Relative Extrema

Find the relative extrema for the following function on the given interval

f(x)=2xx2+1f(x) = \frac{2x}{x^2 + 1} , [2,2][-2, 2]

Posted by Adam Jensen 8 months ago

Related Problems

For the following function draw a rough sketch of the graph for the 3 cases

f(x)=(xa)(xb)(xc)f(x) = \frac{(x - a)}{(x - b)(x - c)}

Case 1: a < b, c

Case 2: b < a < c

Case 3: b, c < a

Find and classify the critical points of the following function

f(x)=x33x29x+2f(x) = x^3 - 3x^2 - 9x + 2

Find the critical points of the following function

f(x)=6x5+33x430x3+100f(x) = 6x^5 + 33x^4 - 30x^3 + 100

Find the absolute extrema of the following function on the given interval

h(x)=xx2h(x) = \frac{x}{x - 2} , [3,5][3, 5]